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Let A=[ (1&0&0@3&1&0@9&3&1)] and B=[b_ij ],1≤i,j≤3. If B=A^99-I, then the value of (b31-b21)/b32 is

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Let A=[ (1&0&0@3&1&0@9&3&1)] and B=[b_ij ],1≤i,j≤3. If B=A^99-I, then the value of (b31-b21)/b32 is

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